X(93) = ISOGONAL CONJUGATE OF X(49)¶
Trilinears
\(sec 3A : sec 3B : sec 3C\)
Barycentrics
\(sin A sec 3A : sin B sec 3B : sin C sec 3C\)
\(1/(a^2 (a^2 - b^2 - c^2) (a^4 + b^4 + c^4 - 2 a^2 b^2 - 2 a^2 c^2 - b^2 c^2)) : : Let OAOBOC be the Kosnita triangle. Let A' be the pole wrt polar circle of line OBOC, and define B' and C' cyclically. The lines AA', BB', CC' concur in :ref:`X(93) <X(93)>\). (Randy Hutson, June 7, 2019) X(93) lies on these lines: 4,562 49,94 186,252 X(93) = isogonal conjugate of X(49) <X(49)>`
Notes
Let OAOBOC be the Kosnita triangle. Let A’ be the pole wrt polar circle of line OBOC, and define B’ and C’ cyclically. The lines AA’, BB’, CC’ concur in X(93). (Randy Hutson, June 7, 2019)
X(93) lies on these lines: 4,562 49,94 186,252
X(93) = isogonal conjugate of X(49)
X(93) = anticomplement of X(34833)
X(93) = X(50)-cross conjugate of X(94)
X(93) = polar conjugate of X(1994)
X(93) = X(2964)-isoconjugate of X(3)