X(60) = ISOGONAL CONJUGATE OF X(12)

Trilinears

\(1/[1 + cos(B - C)] : 1/[1 + cos(C - A)] : 1/[1 + cos(A - B)]\)

\(sec^2 (B/2 - C/2) : :\)

Barycentrics

\(a/[1 + cos(B - C)] : b/[1 + cos(C - A)] : c/[1+ cos(A - B)] Let A'B'C' be the cevian triangle of :ref:`X(21) <X(21)>\). Let A&Prime;, B&Prime;, C&Prime; be the inverse-in-circumcircle of A’, B’, C’. The lines AA&Prime;, BB&Prime;, CC&Prime; concur in X(60). (Randy Hutson, October 15, 2018) X(60) lies on these lines: 1,110 21,960 28,81 36,58 59,1101 86,272 283,284 404,662 757,1014 X(60) = isogonal conjugate of X(12) <X(12)>`

Notes

Let A’B’C’ be the cevian triangle of X(21). Let A&Prime;, B&Prime;, C&Prime; be the inverse-in-circumcircle of A’, B’, C’. The lines AA&Prime;, BB&Prime;, CC&Prime; concur in X(60). (Randy Hutson, October 15, 2018)

X(60) lies on these lines: 1,110 21,960 28,81 36,58 59,1101 86,272 283,284 404,662 757,1014

X(60) = isogonal conjugate of X(12)

X(60) = isotomic conjugate of X(34388)

X(60) = anticomplement of X(34829)

X(60) = X(58)-cross conjugate of X(270)

X(60) = X(i)-beth conjugate of X(j) for these (i,j): (60,849), (1098,1098)

X(60) = crossdifference of every pair of points on line X(2610)X(4024)

X(60) = perspector of ABC and extraversion triangle of X(59)

X(60) = X(75)-isoconjugate of X(181)

X(60) = trilinear square of X(6727)

X(60) = complement of isogonal conjugate of X(36903)