X2661

MIDPOINT OF PU(83)

X2661 is the midpoint of pu(83).
< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 822, 2658 }: Central Line L(822, 2658) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_822 = CROSSDIFFERENCE OF X(1) AND X(29) (6.5481, -0.2984) X_2658 = SUM OF PU(83) (0.5613, 0.1772) X_2661 = MIDPOINT OF PU(83) (0.5590, 0.1773) A B C X822 X2658 X2661 (a, b, c) = (5, 6, 7) | AB = 1

X2661 (MIDPOINT OF PU(83)) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \(f(A,B,C) : f(B,C,A) : f(C,A,B)\), where \(f(A,B,C) = k(a,b,c)/(\sec C + \sec A) + h(a,b,c)/(\sec B + \sec A)\), where \(h(a,b,c) = a/(\sec C + \sec A) + b/(\sec A + \sec B) + c/(\sec B + \sec C)\), and \(k(a,b,c) = a/(\sec B + \sec A) + b/(\sec C + \sec B) + c/(\sec A + \sec C)\)
Barycentrics: \((\sin A)f(A,B,C) : (\sin B)f(B,C,A) : (\sin C)f(C,A,B)\)
Search Value (6, 9, 13): \(0.861137362412\)
▸ Incident Central Lines1 line

{822, 2658}