X2645

MIDPOINT OF PU(79)

X2645 is the midpoint of pu(79).
< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 9, 2640 }: Central Line L(9, 2640) { 2642, 2643 }: Central Line L(2642, 2643) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_9 = MITTENPUNKT (0.5110, 0.1615) X_2640 = CROSSSUM OF PU(78) (1.3971, -0.3206) X_2642 = SUM OF PU(79) (2.3576, 1.9826) X_2643 = DIFFERENCE OF PU(79) (0.7721, 0.0987) X_2645 = MIDPOINT OF PU(79) (0.7263, 0.0444) A B C X9 X2640 X2642 X2643 X2645 (a, b, c) = (5, 6, 7) | AB = 1

X2645 (MIDPOINT OF PU(79)) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \(f(A,B,C) : f(B,C,A) : f(C,A,B)\), where \(f(A,B,C) = k(a,b,c)/(\cot C - \cot A) + h(a,b,c)/(\cot B - \cot A)\), where \(h(a,b,c) = a/(\cot C - \cot A) + b/(\cot A - \cot B) + c/(\cot B - \cot C)\), and \(k(a,b,c) = a/(\cot B - \cot A) + b/(\cot C - \cot B) + c/(\cot A - \cot C)\)
Search Value (6, 9, 13): \(3.226535617911\)
▸ Incident Central Lines2 lines

{9, 2640}, {2642, 2643}