X2628

MIDPOINT OF PU(73)

X2628 is the midpoint of pu(73).
< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 1109, 2624 }: Central Line L(1109, 2624) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_1109 = TRILINEAR SQUARE OF X(523) (0.7246, 0.0705) X_2624 = SUM OF PU(73) (2.8696, 1.7039) X_2628 = MIDPOINT OF PU(73) (0.6720, 0.0304) A B C X1109 X2624 X2628 (a, b, c) = (5, 6, 7) | AB = 1

X2628 (MIDPOINT OF PU(73)) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \(f(A,B,C) : f(B,C,A) : f(C,A,B)\), where \(f(A,B,C) = k(a,b,c) \cot(C - A) + h(a,b,c) \cot(B - A)\), where \(h(a,b,c) = a \cot(C - A) + b \cot(A - B) + c \cot(B - C)\), and \(k(a,b,c) = a \cot(B - A) + b \cot(C - B) + c \cot(A - C)\)
Barycentrics: \((\sin A)f(A,B,C) : (\sin B)f(B,C,A) : (\sin C)f(C,A,B)\)
Search Value (6, 9, 13): \(3.639548031157\)
▸ Incident Central Lines1 line

{1109, 2624}