X2609

MIDPOINT OF PU(70)

X2609 is the midpoint of pu(70).
< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 2245, 2605 }: Central Line L(2245, 2605) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_2245 = -ISOCONJUGATE OF X(759) (1.8169, 2.2770) X_2605 = DIFFERENCE OF PU(71) (6.1667, -1.9052) X_2609 = MIDPOINT OF PU(70) (1.5181, 2.5643) A B C X2245 X2605 X2609 (a, b, c) = (5, 6, 7) | AB = 1

X2609 (MIDPOINT OF PU(70)) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \(f(A,B,C) : f(B,C,A) : f(C,A,B)\), where \(f(A,B,C) = k(a,b,c) \sin(C - A) + h(a,b,c) \sin(B - A)\), where \(h(a,b,c) = a \sin(C - A) + b \sin(A - B) + c \sin(B - C)\), and \(k(a,b,c) = a \sin(B - A) + b \sin(C - B) + c \sin(A - C)\)
Barycentrics: \((\sin A)f(A,B,C) : (\sin B)f(B,C,A) : (\sin C)f(C,A,B)\)
Search Value (6, 9, 13): \(-4.708461871370\)
▸ Incident Central Lines1 line

{2245, 2605}