X2604

MIDPOINT OF PU(69)

X2604 is the midpoint of pu(69).
< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 2599, 2600 }: Central Line L(2599, 2600) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_2599 = SUM OF PU(69) (0.5631, 0.2411) X_2600 = DIFFERENCE OF PU(69) (2.7368, 1.7763) X_2604 = MIDPOINT OF PU(69) (0.5630, 0.2410) A B C X2599 X2600 X2604 (a, b, c) = (5, 6, 7) | AB = 1

X2604 (MIDPOINT OF PU(69)) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \(f(A,B,C) : f(B,C,A) : f(C,A,B)\), where \(f(A,B,C) = k(a,b,c) \sec(C - A) + h(a,b,c) \sec(B - A)\), where \(h(a,b,c) = a \sec(C - A) + b \sec(A - B) + c \sec(B - C)\), and \(k(a,b,c) = a \sec(B - A) + b \sec(C - B) + c \sec(A - C)\)
Barycentrics: \((\sin A)f(A,B,C) : (\sin B)f(B,C,A) : (\sin C)f(C,A,B)\)
Search Value (6, 9, 13): \(-10.693519329315\)
▸ Incident Central Lines1 line

{2599, 2600}