X2598

MIDPOINT OF PU(68)

X2598 is the midpoint of pu(68).
< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 654, 2594 }: Central Line L(654, 2594) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_654 = CROSSDIFFERENCE OF X(1) AND X(5) (2.8235, 1.7291) X_2594 = SUM OF PU(68) (0.5791, 0.2254) X_2598 = MIDPOINT OF PU(68) (0.5790, 0.2254) A B C X654 X2594 X2598 (a, b, c) = (5, 6, 7) | AB = 1

X2598 (MIDPOINT OF PU(68)) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \(f(A,B,C) : f(B,C,A) : f(C,A,B)\), where \(f(A,B,C) = k(a,b,c) \cos(C - A) + h(a,b,c) \cos(B - A)\), where \(h(a,b,c) = a \cos(C - A) + b \cos(A - B) + c \cos(B - C)\), and \(k(a,b,c) = a \cos(B - A) + b \cos(C - B) + c \cos(A - C)\)
Barycentrics: \((\sin A)f(A,B,C) : (\sin B)f(B,C,A) : (\sin C)f(C,A,B)\)
Search Value (6, 9, 13): \(3.597046687682\)
▸ Incident Central Lines1 line

{654, 2594}