X2091¶
2nd STEVANOVIC PERSPECTOR
The bisector AX1 of angle A meets the A-excircle in two points; let A' be the point closer to I, and define B' and C' cyclically. Then triangle A'B'C' is perspective to the intouch triangle, and the perspector is X2091. (Milorad Stevanovic, Hyacinthos #8088, 10/02/03)
X2091 (2nd STEVANOVIC PERSPECTOR) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).¶
"""GEOMETOR construction model for X_2091 = 2nd STEVANOVIC PERSPECTOR."""
from __future__ import annotations
from pathlib import Path
import sympy.geometry as spg
from geometor.model import Model
from geometor.etc.ops import (
central_line,
construct_baseline_triangle,
create_model,
eval_trilinear_point,
promote_point_to_top,
)
from geometor.etc.render import write_center_svg
def construct_x_02091(
model: Model, A: spg.Point, B: spg.Point, C: spg.Point
) -> spg.Point:
"""Construct X_2091 = 2nd STEVANOVIC PERSPECTOR on reference triangle ABC."""
X_2091 = eval_trilinear_point(model, A, B, C, '((1/(b + c - a))*(sin(B/2) + sin(C/2))*sec(A/2))', ID="X_2091", classes=["selected", "target"])
X_57 = eval_trilinear_point(model, A, B, C, '1/(b + c - a)', ID="X_57", classes=["center", "incident"])
X_173 = eval_trilinear_point(model, A, B, C, 'cos(B/2) + cos(C/2) - cos(A/2)', ID="X_173", classes=["center", "incident"])
central_line(model, X_57, X_173, 57, 173, incident=True)
return promote_point_to_top(model, X_2091)
def build_model(
sides: tuple[float, float, float] = (5.0, 6.0, 7.0),
show_guides: bool = False,
) -> Model:
"""Build a `geometor.model.Model` for X_2091 on the given reference triangle."""
model = create_model('X_2091 = 2nd STEVANOVIC PERSPECTOR')
A, B, C = construct_baseline_triangle(model, *sides, show_guides=show_guides)
construct_x_02091(model, A, B, C)
return model
if __name__ == "__main__":
here = Path(__file__).resolve().parent
model_acute = build_model((5.0, 6.0, 7.0))
model_acute.save(str(here / "x-02091.json"))
write_center_svg(
model_acute,
here / "x-02091.svg",
subtitle="(a, b, c) = (5, 6, 7) | AB = 1",
)