X2090

1st STEVANOVIC PERSPECTOR

The bisector AX1 of angle A meets the A-excircle in two points; let A' be the point closer to I, and define B' and C' cyclically. Then triangle A'B'C' is perspective to the medial triangle, and the perspector is X2090. (Milorad Stevanovic, Hyacinthos #8088, 10/02/03)
< A B C >: Reference Triangle △ABC < M_a M_b M_c >: Medial Triangle △M_a M_b M_c [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 2, 174 }: Central Line L(2, 174) { 8, 188 }: Central Line L(8, 188) { 177, 178 }: Central Line L(177, 178) { 9, 362 }: Central Line L(9, 362) { 85, 555 }: Central Line L(85, 555) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) M_a = Midpoint M_a of BC (0.8061, 0.2999) M_b = Midpoint M_b of CA (0.3061, 0.2999) M_c = Midpoint M_c of AB (0.5000, 0.0000) X_2 = CENTROID (0.5374, 0.2000) X_174 = YFF CENTER OF CONGRUENCE (0.5813, 0.2549) X_8 = NAGEL POINT (0.4694, 0.1333) X_188 = 2nd MID-ARC POINT OF ANTICOMPLEMENTARY TRIANGLE (0.5245, 0.1802) X_177 = 1st MID-ARC POINT (0.5862, 0.2654) X_178 = 2nd MID-ARC POINT (0.5439, 0.2098) X_9 = MITTENPUNKT (0.5110, 0.1615) X_362 = CONGRUENT CIRCUMCIRCLES ISOSCELIZER POINT (0.5299, 0.2081) X_85 = ISOTOMIC CONJUGATE OF X(9) (0.5610, 0.2421) X_555 = (X(1),X(158))-ANSWER TO QUESTION A (0.5982, 0.2990) X_2090 = 1st STEVANOVIC PERSPECTOR (0.5155, 0.1725) A B C Ma Mb Mc X2 X174 X8 X188 X177 X178 X9 X362 X85 X555 X2090 (a, b, c) = (5, 6, 7) | AB = 1

X2090 (1st STEVANOVIC PERSPECTOR) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \(f(A,B,C) : f(B,C,A) : f(C,A,B)\), where \(f(A,B,C) = (\sin B/2 + \sin C/2) \csc A\)
Barycentrics: \((\sin A)f(A,B,C) : (\sin B)f(B,C,A) : (\sin C)f(C,A,B)\)
Search Value (6, 9, 13): \(3.356486961348\)
▸ Incident Central Lines6 lines

{2, 174}, {8, 188}, {9, 362}, {85, 555}, {177, 178}, {312, 556}

▸ Functional Relations2 relations