X2025¶
RADICAL TRACE OF GALLATLY AND 2nd LEMOINE CIRCLES
X2025 (RADICAL TRACE OF GALLATLY AND 2nd LEMOINE CIRCLES) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).¶
"""GEOMETOR construction model for X_2025 = RADICAL TRACE OF GALLATLY AND 2nd LEMOINE CIRCLES."""
from __future__ import annotations
from pathlib import Path
import sympy.geometry as spg
from geometor.model import Model
from geometor.etc.ops import (
central_line,
circumcenter_of,
construct_baseline_triangle,
create_model,
eval_trilinear_point,
midpoint,
promote_point_to_top,
symmedian_point_of,
)
from geometor.etc.render import write_center_svg
def construct_x_02025(
model: Model, A: spg.Point, B: spg.Point, C: spg.Point
) -> spg.Point:
"""Construct X_2025 = RADICAL TRACE OF GALLATLY AND 2nd LEMOINE CIRCLES on reference triangle ABC."""
X_39 = eval_trilinear_point(model, A, B, C, 'a*(b**(2) + c**(2))', ID="X_39", classes=["center"])
X_1570 = eval_trilinear_point(model, A, B, C, 'a*(cot(A) + cot(omega) - 4*tan(omega) )', ID="X_1570", classes=["center"])
X_2025 = midpoint(model, X_39, X_1570, ID="X_2025", classes=["selected", "target"], guide=False)
X_3 = circumcenter_of(model, A, B, C, ID="X_3", classes=["center", "incident"])
X_6 = symmedian_point_of(model, A, B, C, ID="X_6", classes=["center", "incident"])
central_line(model, X_3, X_6, 3, 6, incident=True)
return promote_point_to_top(model, X_2025)
def build_model(
sides: tuple[float, float, float] = (5.0, 6.0, 7.0),
show_guides: bool = False,
) -> Model:
"""Build a `geometor.model.Model` for X_2025 on the given reference triangle."""
model = create_model('X_2025 = RADICAL TRACE OF GALLATLY AND 2nd LEMOINE CIRCLES')
A, B, C = construct_baseline_triangle(model, *sides, show_guides=show_guides)
construct_x_02025(model, A, B, C)
return model
if __name__ == "__main__":
here = Path(__file__).resolve().parent
model_acute = build_model((5.0, 6.0, 7.0))
model_acute.save(str(here / "x-02025.json"))
write_center_svg(
model_acute,
here / "x-02025.svg",
subtitle="(a, b, c) = (5, 6, 7) | AB = 1",
)