X1994¶
ORTHOCORRESPONDENT OF X5
Let OAOBOC be the Kosnita triangle. Let A' be the trilinear pole of line OBOC, and define B' and C' cyclically. The lines AA', BB', CC' concur in X1994. (Randy Hutson, March 21, 2019)
X1994 (ORTHOCORRESPONDENT OF X5) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).¶
Constructed Elements
Central Lines: {2, 6}, {52, 54}
Related Centers: X2963 (BARYCENTRIC PRODUCT X17*X18), X2 (CENTROID), X6 (SYMMEDIAN POINT), X52 (ORTHOCENTER OF ORTHIC TRIANGLE), X54 (KOSNITA POINT)
Trilinears: \(f(a,b,c) : f(b,c,a) : f(c,a,b)\), where \(f(a,b,c) = a[b^{2}c^{2} - 16(\operatorname{area}(ABC))^{2}]\)
Barycentrics: \(a^{2} - R^{2} : :\)
Search Value (6, 9, 13): \(-1.238671087458\)
Alternate Coordinates1 form
Trilinears: \(\cos 3A \csc 2A : \cos 3B \csc 2B : \cos 3C \csc 2C ( M. Iliev, 4/12/07)\)