X1484

REFLECTION OF X5 IN X11

X1484 is the reflection of X5 in X11.
< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 5, 11 }: Feuerbach Line { 1, 5 }: Feuerbach Line { 30, 104 }: Central Line L(30, 104) { 3, 149 }: Central Line L(3, 149) { 100, 140 }: Central Line L(100, 140) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_5 = NINE-POINT CENTER (0.5561, 0.2489) X_11 = FEUERBACH POINT (0.7347, 0.0667) X_1 = INCENTER (0.5714, 0.2333) X_30 = EULER INFINITY POINT (0.7469, 0.7481) X_104 = ANTIPODE OF X(100) (0.8571, -0.2624) X_3 = CIRCUMCENTER (0.5000, 0.1021) X_149 = REFLECTION OF X(20) IN X(104) (1.3265, -0.3333) X_100 = ANTICOMPLEMENT OF FEUERBACH POINT (0.1429, 0.4666) X_140 = MIDPOINT OF X(3) AND X(5) (0.5281, 0.1755) X_1484 = REFLECTION OF X(5) IN X(11) (0.9133, -0.1156) A B C X5 X11 X1 X30 X104 X3 X149 X100 X140 X1484 (a, b, c) = (5, 6, 7) | AB = 1

X1484 (REFLECTION OF X5 IN X11) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \(f(a,b,c) : f(b,c,a) : f(c,a,b)\), where \(f(a,b,c) = 4r - (2r + R)\cos(B - C)\)
Barycentrics: \(af(a,b,c) : bf(b,c,a) : cf(c,a,b)\)
Search Value (6, 9, 13): \(4.733398500856\)
▸ Incident Central Lines6 lines

{1, 5}, {3, 149}, {30, 104}, {100, 140}, {153, 381}, {528, 549}

▸ Functional Relations2 relations