X1320

ISOGONAL CONJUGATE OF X1319

< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 145, 149 }: Central Line L(145, 149) { 8, 11 }: Central Line L(8, 11) { 1, 88 }: Central Line L(1, 88) { 4, 145 }: Central Line L(4, 145) { 7, 528 }: Central Line L(7, 528) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_145 = ANTICOMPLEMENT OF NAGEL POINT (0.6735, 0.3333) X_149 = REFLECTION OF X(20) IN X(104) (1.3265, -0.3333) X_8 = NAGEL POINT (0.4694, 0.1333) X_11 = FEUERBACH POINT (0.7347, 0.0667) X_1 = INCENTER (0.5714, 0.2333) X_88 = ISOGONAL CONJUGATE OF X(44) (1.0000, 0.0000) X_4 = ORTHOCENTER (0.6122, 0.3958) X_7 = GERGONNE POINT (0.5903, 0.2769) X_528 = DIRECTION OF VECTOR AX + BX + CX, where X = X(11) (1.0237, -0.1286) X_1320 = ISOGONAL CONJUGATE OF X(1319) (1.0000, 0.0000) A B C X145 X149 X8 X11 X1 X88 X4 X7 X528 X1320 (a, b, c) = (5, 6, 7) | AB = 1

X1320 (ISOGONAL CONJUGATE OF X1319) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \(f(a,b,c) : f(b,c,a) : f(c,a,b)\), where \(f(a,b,c) = (b + c - a)/ (b + c - 2a)\)
Barycentrics: \(af(a,b,c) : bf(b,c,a) : cf(c,a,b)\)
Search Value (6, 9, 13): \(0.778780883938\)

X1320 lies on the Darboux septic.

▸ Incident Central Lines12 lines

{1, 88}, {2, 1000}, {4, 145}, {7, 528}, {8, 11}, {9, 644}, {21, 643}, {80, 519}, {104, 517}, {518, 1156}, {900, 1120}, {1022, 1280}

▸ Functional Relations13 relations

Notes

Let DEF be the intouch triangle. Let Ha be the orthocenter of IBC. Let A1 be the point, other than A, where AI meets the circumcircle. Let \(t_{a}\) be the tangent to the circle (DHaA1) at Ha, and define \(t_{b}\) and \(t_{c}\) cyclically. The lines \(t_{a}\), \(t_{b}\) , \(t_{c}\) concur in X1320. (Angel Montesdeoca, September 3, 2020)