X1139¶
OUTER PENTAGON POINT
Let A' be the outermost vertex of the regular pentagon erected outward on side BC of ABC. Define B' and C' cyclically. Then triangle A'B'C' is perspective to ABC, and the perspector is X1139. (Steve Sigur and Antreas Hatzipolakis, #5246, 12/31/02; generalizations to n-gons, for odd n, by Milorad R. Stevanovic, #5253, 5256)
X1139 (OUTER PENTAGON POINT) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).¶
Constructed Elements
Central Lines: {6, 1140}, {1, 3369}
Related Centers: X3394 (SIN(A + π/5) POINT), X3397 (SEC(A + 2π/5) POINT), X6 (SYMMEDIAN POINT), X1140 (INNER PENTAGON POINT), X1 (INCENTER), X3369 (SIN(A - 2π/5) POINT)
Trilinears: \((\csc A)/(\cot A + \cot 2\pi /5) : (\csc B)/(\cot B + \cot 2\pi /5) : (\csc C)/(\cot C + \cot 2\pi /5)\)
Barycentrics: \(1/(\cot A + \cot 2\pi /5) : 1/(\cot B + \cot 2\pi /5) : 1/(\cot C + \cot 2\pi /5)\)
Search Value (6, 9, 13): \(-0.882375056596\)
Alternate Coordinates1 form
Trilinears: \(\csc(A + 2\pi /5) : \csc(B + 2\pi /5) : \csc(C + 2\pi /5)\) (Joe Goggins, Oct. 19, 2005)
Functional Relations2 relations
X1139 = isogonal conjugate of X3396
X1139 = X3394-cross conjugate of X3397