X314

ISOTOMIC CONJUGATE OF X65

< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 4, 69 }: Central Line L(4, 69) { 1, 75 }: Central Line L(1, 75) { 99, 104 }: Central Line L(99, 104) { 21, 261 }: Central Line L(21, 261) { 7, 310 }: Central Line L(7, 310) { 9, 312 }: Central Line L(9, 312) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_65 = ORTHOCENTER OF THE INTOUCH TRIANGLE (0.6041, 0.2933) X_4 = ORTHOCENTER (0.6122, 0.3958) X_69 = SYMMEDIAN POINT OF THE ANTICOMPLEMENTARY TRIANGLE (0.4122, 0.0654) X_1 = INCENTER (0.5714, 0.2333) X_75 = ISOTOMIC CONJUGATE OF INCENTER (0.4988, 0.1682) X_99 = STEINER POINT (0.1109, 0.4322) X_104 = ANTIPODE OF X(100) (0.8571, -0.2624) X_21 = SCHIFFLER POINT (0.5287, 0.1771) X_261 = ISOTOMIC CONJUGATE OF X(12) (0.5072, 0.1625) X_7 = GERGONNE POINT (0.5903, 0.2769) X_310 = ISOTOMIC CONJUGATE OF X(42) (0.4762, 0.1536) X_9 = MITTENPUNKT (0.5110, 0.1615) X_312 = ISOTOMIC CONJUGATE OF X(57) (0.4256, 0.1081) X_314 = ISOTOMIC CONJUGATE OF X(65) (0.4457, 0.1206) A B C X65 X4 X69 X1 X75 X99 X104 X21 X261 X7 X310 X9 X312 X314 (a, b, c) = (5, 6, 7) | AB = 1

X314 (ISOTOMIC CONJUGATE OF X65) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \(f(a,b,c) : f(b,c,a) : f(c,a,b)\), where \(f(a,b,c) = b^{2}c^{2}(b + c - a)/(b + c)\)
Barycentrics: \(g(a,b,c) : g(b,c,a) : g(c,a,b)\), where \(g(a,b,c) = bc(b + c - a)/(b + c)\)
Search Value (6, 9, 13): \(5.033660717966\)
▸ Incident Central Lines16 lines

{1, 75}, {2, 941}, {4, 69}, {6, 981}, {7, 310}, {9, 312}, {21, 261}, {29, 1039}, {58, 987}, {79, 320}, {80, 313}, {81, 321}, {84, 309}, {99, 104}, {256, 350}, {294, 645}

▸ Functional Relations14 relations

Notes

Let D and E be the intersections of line X1X3 with lines PU(3) and PU(6), respectively. Let D' and E' be the isogonal conjugates of D and E, respectively. Let D″ and E″ be the isotomic conjugates of D and E, respectively. Then X314 = D'D″ ∩E'E″. (Randy Hutson, December 26, 2015)

Let A4B4C4 be the 4th Conway triangle. Let A' be the cevapoint of B4 and C4, and define B' and C' cyclically. The lines AA', BB', CC' concur in X314. (Randy Hutson, December 10, 2016)

Let A5B5C5 be the 5th Conway triangle. Let A' be the cevapoint of B5 and C5, and define B' and C' cyclically. The lines AA', BB', CC' concur in X314. (Randy Hutson, December 10, 2016)