X185¶
NAGEL POINT OF THE ORTHIC TRIANGLE
X185 (NAGEL POINT OF THE ORTHIC TRIANGLE) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).¶
Constructed Elements
Central Lines: {3, 49}, {4, 51}
Related Centers: X1105 (CEVAPOINT OF X3 AND X4), X3 (CIRCUMCENTER), X49 (CENTER OF SINE-TRIPLE-ANGLE CIRCLE), X4 (ORTHOCENTER), X51 (CENTROID OF ORTHIC TRIANGLE)
Alternate Coordinates2 forms
Trilinears: \((\cos A)(\cos^{2} B + \cos^{2} C) : :\)
Trilinears: \(a(b^{2} + c^{2} - a^{2})[2a^{2}(b^{2} - c^{2})^{2} - a^{4}(b^{2} + c^{2}) - (b^{2} - c^{2})^{2}(b^{2} + c^{2})] : :\)
Incident Central Lines16 lines
Functional Relations21 relations
X185 = reflection of Xi in Xj for these (i,j): (4, 389), (125, 974)
X185 = isogonal conjugate of X1105
X185 = Xi-Ceva conjugate of Xj for these (i,j): (3, 417), (4, 235)
X185 = crosspoint of X3 and X4
X185 = crosssum of Xi and Xj for these (i,j): (3, 4), (25, 1249)
X185 = anticomplement of X5907
X185 = bicentric sum of PU(17)
X185 = orthology center of orthic and half-altitude triangles
X185 = orthic-isotomic conjugate of X1843
X185 = eigencenter of cevian triangle of X648
X185 = eigencenter of anticevian triangle of X647
X185 = trilinear product of vertices of 2nd Hyacinth triangle
X185 = excentral-to-ABC functional image of X8
X185 = polar-circle-inverse of X34170
Notes¶
Let Ha be the foot of the A-altitude. Let Ba and Ca be the feet of perpendiculars from Ha to CA and AB, respectively. Let Ga be the centroid of HaBaCa. Define Gb and Gc cyclically. The lines HaGa, HbGb, HcGc concur in X185. (Randy Hutson, December 26, 2015)
Let Ha, Hb, Hc be the orthocenters of the A-, B-, and C-altimedial triangles. X185 is the orthocenter of HaHbHc. (Randy Hutson, March 25, 2016)
Let P be a point on the circumcircle. Let Pa be the orthogonal projection of P on the A-altitude, and define Pb, Pc cyclically. The locus of the orthocenter of PaPbPc as P varies is an ellipse centered at X185. See also X9730. (Randy Hutson, March 25, 2016)
Let A'B'C' be the midheight triangle. Let AB, AC be the orthogonal projections of A' on CA, AB, resp. Define BC, BA, CA, CB cyclically. Let A″ = CAAC∩ABBA, and define B″ and C″ cyclically. Triangle A″B″C″ is homothetic to ABC at X6 and perspective to the orthic triangle at X185. (Randy Hutson, March 29, 2020)