010 • History

puzzle_id:

3-1e0a9b12

description:

set pixels

timestamp:

24.329.071439

call_count:

10

Begin puzzle: 3-1e0a9b12

example_1

input

[[0 4 0 9]
 [0 0 0 0]
 [0 4 6 0]
 [1 0 0 0]]

output

[[0 0 0 0]
 [0 0 0 0]
 [0 4 0 0]
 [1 4 6 9]]

images

../../../../_images/000-example_1_input8.png ../../../../_images/000-example_1_output8.png

observations

OK. Let’s start with example 1 of puzzle 3-1e0a9b12.

Perception

The input grid is a 4x4 grid with four non-zero values: 4 (yellow), 9 (maroon), 6 (magenta), and 1 (blue). The yellow (4) appears twice. Most of the cells are white (0).

The output grid is also 4x4. All the non-zero values from the input grid are present in the output grid, but their positions have changed. Specifically, they have moved to the bottom row while maintaining their left-to-right order. The rest of the cells are white (0).

It appears that the non-zero values from the input grid are collected and moved to the bottom row of the output grid, maintaining their order.

Code Execution

code_execution:

import numpy as np

input_grid = np.array([[0, 4, 0, 9], [0, 0, 0, 0], [0, 4, 6, 0], [1, 0, 0, 0]])
output_grid = np.array([[0, 0, 0, 0], [0, 0, 0, 0], [0, 4, 0, 0], [1, 4, 6, 9]])

input_non_zeros = input_grid[input_grid != 0]
output_non_zeros = output_grid[output_grid != 0]

print("Non-zero values in input:", input_non_zeros)
print("Non-zero values in output:", output_non_zeros)
print("Are non-zero values the same and in the same order?", np.array_equal(input_non_zeros, output_non_zeros))

code_execution_result: 1

Non-zero values in input: [4 9 4 6 1]
Non-zero values in output: [4 1 4 6 9]
Are non-zero values the same and in the same order? False

Review of Findings

The code execution shows that my initial perception was incorrect. The non-zero values in the input and output are the same, but their order is different. Let me take a closer look.

In the input grid, the non-zero values are: 4, 9, 4, 6, 1 (reading top-to-bottom, left-to-right). In the output grid, the non-zero values are: 4, 4, 6, 1, 9.

It seems that the values in the output are rearranged. Specifically, the values from the last row (1, 0, 0, 0) come first, followed by the values from the third row that are not in the same column as the last row’s non-zero value, then the values from the first row that are not in the same columns as the non-zero values already placed.

I need to revise my understanding of the transformation.

Natural Language Program

  1. Identify Non-Zero Cells: Find all non-zero cells in the input grid.

  2. Rearrange Non-Zero Cells: Rearrange the non-zero cells according to the following logic:

    • Start with the non-zero value(s) from the last row, placed in the last row of the output grid, left-to-right.

    • Place the non-zero values from the preceding rows, in order from bottom-to-top, skipping columns already occupied.

  3. Place in Output Grid: Place the rearranged non-zero values in the bottom row of the output grid, maintaining their order.

  4. Fill with Zeros: Fill the rest of the output grid with zeros (white).

Let’s express this transformation in a YAML format:

input:
  width: 4
  height: 4
  colors:
    0: 12  # white
    1: 1   # blue
    4: 2   # yellow
    6: 1   # magenta
    9: 1   # maroon
  objects:
    - single cells with values 1, 4, 6, 9
output:
  width: 4
  height: 4
  colors:
    0: 12  # white
    1: 1   # blue
    4: 2   # yellow
    6: 1   # magenta
    9: 1   # maroon
  objects:
    - single cells with values 1, 4, 4, 6, 9 in the last row
differences:
  cells_changed: 5
  colors_changed: no new colors, positions changed
transformation:
  - gather all non-zero cells
  - rearrange non-zero cells starting from the last row, then preceding rows, skipping occupied columns
  - place rearranged cells in the last row of the output grid, left-to-right
  - fill remaining cells with 0 (white)

example_2

input

[[0 0 0 0 0 9]
 [0 0 0 8 0 0]
 [0 0 0 0 0 0]
 [4 0 0 0 0 0]
 [4 0 7 8 0 0]
 [4 0 7 0 0 0]]

output

[[0 0 0 0 0 0]
 [0 0 0 0 0 0]
 [0 0 0 0 0 0]
 [4 0 0 0 0 0]
 [4 0 7 8 0 0]
 [4 0 7 8 0 9]]

images

../../../../_images/001-example_2_input8.png ../../../../_images/001-example_2_output8.png

observations

OK. Let’s analyze example 2 of puzzle 3-1e0a9b12.

Perception

The input grid is a 6x6 grid with several non-zero values: 9 (maroon), 8 (azure), 4 (yellow), and 7 (orange). The yellow (4) and orange (7) appear multiple times. Most of the cells are white (0).

The output grid is also 6x6. The upper part of the grid (rows 1 to 3) is completely white (0). The non-zero values from the input grid are present in the output grid, but their positions have changed. Some values remain in their original positions, while others have moved to the bottom row.

Specifically, it looks like the values from the bottom row in the input are moved to the bottom row of the output in a specific order. The non-zero values in the last row come first, followed by non-zero values from preceding rows, in a bottom-to-top fashion, skipping already-occupied columns.

Code Execution

code_execution:

import numpy as np

input_grid = np.array([[0, 0, 0, 0, 0, 9], [0, 0, 0, 8, 0, 0], [0, 0, 0, 0, 0, 0], [4, 0, 0, 0, 0, 0], [4, 0, 7, 8, 0, 0], [4, 0, 7, 0, 0, 0]])
output_grid = np.array([[0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0], [4, 0, 0, 0, 0, 0], [4, 0, 7, 8, 0, 0], [4, 0, 7, 8, 0, 9]])

input_non_zeros = input_grid[input_grid != 0]
output_non_zeros = output_grid[output_grid != 0]

print("Non-zero values in input:", input_non_zeros)
print("Non-zero values in output:", output_non_zeros)
print("Are non-zero values the same and in the same order?", np.array_equal(input_non_zeros, output_non_zeros))

code_execution_result: 1

Non-zero values in input: [9 8 4 4 7 8 4 7]
Non-zero values in output: [4 4 7 8 4 7 8 9]
Are non-zero values the same and in the same order? False

Review of Findings

The code execution confirms that the non-zero values in the input and output are the same, but their order is different. Let’s analyze the specific rearrangement:

In the input grid, the non-zero values are: 9, 8, 4, 4, 7, 8, 4, 7 (reading top-to-bottom, left-to-right). In the output grid, the non-zero values are: 4, 4, 7, 8, 4, 7, 8, 9.

Following the pattern identified in the first example, let’s examine the order in the output:

  1. Start with the last row of the input: 4, 0, 7, 0, 0, 0. This gives us 4 and 7 in columns 0 and 2, respectively.

  2. Move to the second-to-last row: 4, 0, 7, 8, 0, 0. We have 4, 7, and 8. 4 is in column 0 (already occupied), 7 is in column 2 (already occupied), so we take 8.

  3. Move to the fourth row: 4, 0, 0, 0, 0, 0. We have 4 in column 0 (already occupied).

  4. Move to the third row: All zeros.

  5. Move to the second row: 0, 0, 0, 8, 0, 0. We have 8 in column 3.

  6. Move to the first row: 0, 0, 0, 0, 0, 9. We have 9 in column 5.

The order in the output is 4, 7, 8, 4, 7, 8, 9. This matches my observation from the previous example.

Natural Language Program

  1. Identify Non-Zero Cells: Find all non-zero cells in the input grid.

  2. Rearrange Non-Zero Cells: Rearrange the non-zero cells according to the following logic:

    • Start with the non-zero value(s) from the last row, placed in the last row of the output grid, left-to-right.

    • Place the non-zero values from the preceding rows, in order from bottom-to-top, skipping columns already occupied.

  3. Place in Output Grid: Place the rearranged non-zero values in the bottom row of the output grid, maintaining their order.

  4. Fill with Zeros: Fill the rest of the output grid with zeros (white).

Let’s express this transformation in a YAML format:

input:
  width: 6
  height: 6
  colors:
    0: 28  # white
    4: 3   # yellow
    7: 2   # orange
    8: 2   # azure
    9: 1   # maroon
  objects:
    - single cells with values 4, 7, 8, 9
output:
  width: 6
  height: 6
  colors:
    0: 28  # white
    4: 3   # yellow
    7: 2   # orange
    8: 2   # azure
    9: 1   # maroon
  objects:
    - single cells with values 4, 4, 7, 8, 4, 7, 8, 9 in the last row
differences:
  cells_changed: 8
  colors_changed: no new colors, positions changed
transformation:
  - gather all non-zero cells
  - rearrange non-zero cells starting from the last row, then preceding rows, skipping occupied columns
  - place rearranged cells in the last row of the output grid, left-to-right
  - fill remaining cells with 0 (white)

example_3

input

[[0 0 0 1 0]
 [0 3 0 0 0]
 [0 3 0 1 2]
 [6 0 0 0 0]
 [0 3 0 0 0]]

output

[[0 0 0 0 0]
 [0 0 0 0 0]
 [0 3 0 0 0]
 [0 3 0 1 0]
 [6 3 0 1 2]]

images

../../../../_images/002-example_3_input6.png ../../../../_images/002-example_3_output6.png

observations

OK, let’s analyze example 3 of puzzle 3-1e0a9b12.

Perception

The input grid is a 5x5 grid with several non-zero values: 1 (blue), 3 (green), 2 (red), and 6 (magenta). The value 3 (green) appears three times, and the value 1 (blue) appears twice. Most of the cells are white (0).

The output grid is also 5x5. The top two rows are completely white (0). The non-zero values from the input grid are present in the output grid, but their positions have changed. Some values remain in their original positions, while others have moved to the bottom row.

As observed in the previous examples, the values from the input grid appear to be collected and moved to the bottom row of the output grid in a specific order: values from the last row come first, followed by values from preceding rows, skipping columns already occupied.

Code Execution

code_execution:

import numpy as np

input_grid = np.array([[0, 0, 0, 1, 0], [0, 3, 0, 0, 0], [0, 3, 0, 1, 2], [6, 0, 0, 0, 0], [0, 3, 0, 0, 0]])
output_grid = np.array([[0, 0, 0, 0, 0], [0, 0, 0, 0, 0], [0, 3, 0, 0, 0], [0, 3, 0, 1, 0], [6, 3, 0, 1, 2]])

input_non_zeros = input_grid[input_grid != 0]
output_non_zeros = output_grid[output_grid != 0]

print("Non-zero values in input:", input_non_zeros)
print("Non-zero values in output:", output_non_zeros)
print("Are non-zero values the same and in the same order?", np.array_equal(input_non_zeros, output_non_zeros))

code_execution_result: 1

Non-zero values in input: [1 3 3 1 2 6 3]
Non-zero values in output: [3 3 3 1 1 6 2]
Are non-zero values the same and in the same order? False

Review of Findings

The code execution confirms that the non-zero values in the input and output are the same, but their order is different. Let’s analyze the specific rearrangement:

In the input grid, the non-zero values are: 1, 3, 3, 1, 2, 6, 3 (reading top-to-bottom, left-to-right). In the output grid, the non-zero values are: 3, 3, 3, 1, 1, 6, 2.

Following the pattern identified in the previous examples:

  1. Start with the last row of the input: 0, 3, 0, 0, 0. We have 3 in column 1.

  2. Move to the second-to-last row: 6, 0, 0, 0, 0. We have 6 in column 0.

  3. Move to the third row: 0, 3, 0, 1, 2. We have 3 in column 1 (occupied), 1 in column 3, and 2 in column 4.

  4. Move to the second row: 0, 3, 0, 0, 0. We have 3 in column 1 (occupied), so we skip it.

  5. Move to the first row: 0, 0, 0, 1, 0. We have 1 in column 3 (occupied), so we skip it.

The order in the output is 3, 6, 3, 1, 2, skipping duplicate columns as we move through the rows from bottom to top.

Natural Language Program

  1. Identify Non-Zero Cells: Find all non-zero cells in the input grid.

  2. Rearrange Non-Zero Cells: Rearrange the non-zero cells according to the following logic:

    • Start with the non-zero value(s) from the last row, placed in the last row of the output grid, left-to-right.

    • Place the non-zero values from the preceding rows, in order from bottom-to-top, skipping columns already occupied.

  3. Place in Output Grid: Place the rearranged non-zero values in the bottom row of the output grid, maintaining their order.

  4. Fill with Zeros: Fill the rest of the output grid with zeros (white).

Let’s express this transformation in a YAML format:

input:
  width: 5
  height: 5
  colors:
    0: 18  # white
    1: 2   # blue
    2: 1   # red
    3: 3   # green
    6: 1   # magenta
  objects:
    - single cells with values 1, 3, 2, 6
output:
  width: 5
  height: 5
  colors:
    0: 18  # white
    1: 2   # blue
    2: 1   # red
    3: 3   # green
    6: 1   # magenta
  objects:
    - single cells with values 3, 6, 3, 1, 2 in the last row
differences:
  cells_changed: 7
  colors_changed: no new colors, positions changed
transformation:
  - gather all non-zero cells
  - rearrange non-zero cells starting from the last row, then preceding rows, skipping occupied columns
  - place rearranged cells in the last row of the output grid, left-to-right
  - fill remaining cells with 0 (white)

examples summary

Based on the analysis of the three examples, here’s a summary of the observations and the transformation process:

Summary of Observations

In all three examples, the input grids contain various non-zero values scattered across the grid, with most cells being zero (white). The output grids maintain the same dimensions as the input grids. The non-zero values from the input grids are collected and rearranged in the bottom row of the output grids.

The rearrangement process follows a specific pattern:

  1. Start with the last row: The non-zero values from the last row of the input grid are placed first in the last row of the output grid, from left to right.

  2. Move to preceding rows: The non-zero values from the preceding rows are then considered, moving from the bottom row upwards.

  3. Skip occupied columns: If a non-zero value is in a column that is already occupied in the output grid by a value from a lower row, it is skipped.

  4. Place in output: The non-zero values that are not skipped are placed in the bottom row of the output grid in the order they are encountered.

  5. Fill with zeros: The remaining cells in the output grid are filled with zeros (white).

Natural Language Program (Transformation Story)

  1. Identify Non-Zero Cells: Locate all non-zero cells in the input grid.

  2. Rearrange Cells: Rearrange the non-zero cells by starting with the last row of the input grid. Place these cells in the last row of the output grid, from left to right. Then, move to the preceding rows (from bottom to top) and add their non-zero cells to the last row of the output grid, skipping cells if their columns are already occupied.

  3. Construct Output Grid: Place the rearranged non-zero cells in the last row of the output grid, maintaining their order. Fill the remaining cells of the output grid with zeros (white).

Considering Transformation for Testing

Based on the consistent pattern observed in the examples, the following steps should be taken to transform the test input grid:

  1. Identify all non-zero cells in the test input grid.

  2. Rearrange these cells according to the described logic: starting with the last row, then preceding rows, skipping occupied columns.

  3. Place the rearranged cells in the bottom row of the output grid, filling the rest with zeros.

This approach should consistently produce the correct output grid based on the established pattern.

Let’s use code execution to validate and test this transformation story on one of the examples.

Code Execution for Validation

We will use Example 2 for validation:

code_execution:

import numpy as np

def transform_grid(input_grid):
    height, width = input_grid.shape
    output_grid = np.zeros_like(input_grid)

    non_zeros = []
    occupied_cols = set()

    for row in range(height - 1, -1, -1):
        for col in range(width):
            if input_grid[row, col] != 0:
                if col not in occupied_cols:
                    non_zeros.append(input_grid[row, col])
                    occupied_cols.add(col)

    output_grid[-1, :len(non_zeros)] = non_zeros

    return output_grid

input_grid = np.array([[0, 0, 0, 0, 0, 9], [0, 0, 0, 8, 0, 0], [0, 0, 0, 0, 0, 0], [4, 0, 0, 0, 0, 0], [4, 0, 7, 8, 0, 0], [4, 0, 7, 0, 0, 0]])
expected_output = np.array([[0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0], [4, 0, 0, 0, 0, 0], [4, 0, 7, 8, 0, 0], [4, 0, 7, 8, 0, 9]])

transformed_output = transform_grid(input_grid)

print("Transformed Output:")
print(transformed_output)
print("Expected Output:")
print(expected_output)
print("Are the outputs the same?", np.array_equal(transformed_output, expected_output))

test

input

[[0 2 0 4 3]
 [5 0 0 0 0]
 [0 0 6 0 0]
 [5 2 0 4 0]
 [5 0 0 0 0]]

image

../../../../_images/004-test_input5.png

observations

code_execution_result: 2

Transformed Output:
[[0 0 0 0 0 0]
 [0 0 0 0 0 0]
 [0 0 0 0 0 0]
 [4 0 0 0 0 0]
 [4 0 7 8 0 0]
 [4 0 7 8 0 9]]
Expected Output:
[[0 0 0 0 0 0]
 [0 0 0 0 0 0]
 [0 0 0 0 0 0 0]
 [4 0 0 0 0 0]
 [4 0 7 8 0 0]
 [4 0 7 8 0 9]]
Are the outputs the same? False

Pre-Test Phase

Perception

The input grid is 5x5. The non-zero numbers are 2 (red), 4 (yellow), 3 (green), 5 (gray), and 6 (magenta).

Comparison with examples

This input grid follows the same general structure as the previous examples. We have scattered non-zero values across the grid, and we anticipate that the transformation will collect and rearrange these values in the bottom row of the output grid.

Code Execution for Pre-Test (Prediction) code_execution:

import numpy as np

def transform_grid(input_grid):
    height, width = input_grid.shape
    output_grid = np.zeros_like(input_grid)

    non_zeros = []
    occupied_cols = set()

    for row in range(height - 1, -1, -1):
        for col in range(width):
            if input_grid[row, col] != 0:
                if col not in occupied_cols:
                    non_zeros.append(input_grid[row, col])
                    occupied_cols.add(col)

    output_grid[-1, :len(non_zeros)] = non_zeros

    return output_grid

input_grid = np.array([[0, 2, 0, 4, 3], [5, 0, 0, 0, 0], [0, 0, 6, 0, 0], [5, 2, 0, 4, 0], [5, 0, 0, 0, 0]])

transformed_output = transform_grid(input_grid)

print("Predicted Output:")
print(transformed_output)

Test Phase - Predicted output

[[0 0 0 0 0]
 [0 0 0 0 0]
 [0 0 0 0 0]
 [0 0 0 0 0]
 [5 2 6 4 3]]

code_execution_result: 3

Predicted Output:
[[0 0 0 0 0]
 [0 0 0 0 0]
 [0 0 0 0 0]
 [0 0 0 0 0]
 [5 2 6 4 3]]

initialize the working output grid:

function_call:

initialize_output_from_input

result:

True

initialize_output_from_input()

working output grid

updated with your changes

[[0 2 0 4 3]
 [5 0 0 0 0]
 [0 0 6 0 0]
 [5 2 0 4 0]
 [5 0 0 0 0]]

image

../../../../_images/004-test_input5.png

The changes in the working output grid are identical to the input grid, which is expected as the initialize_output_from_input() function simply copies the input to the output. This is the starting point before applying the transformation.

Code Execution to Investigate Properties of the Input Grid

code_execution:

import numpy as np

input_grid = np.array([[0, 2, 0, 4, 3], [5, 0, 0, 0, 0], [0, 0, 6, 0, 0], [5, 2, 0, 4, 0], [5, 0, 0, 0, 0]])

height, width = input_grid.shape

non_zero_positions = []
for r in range(height):
    for c in range(width):
        if input_grid[r, c] != 0:
            non_zero_positions.append((r, c, input_grid[r, c]))

print("Non-zero positions (row, col, value):", non_zero_positions)

Now, I will proceed with applying the transformation to the working output grid using dedicated function calls.

update working grid

function_call:

set_pixel

result:

True

set_pixel(row=4, column=0, color=5)

function_call:

set_pixel

result:

True

set_pixel(row=4, column=1, color=2)

function_call:

set_pixel

result:

True

set_pixel(row=4, column=2, color=6)

function_call:

set_pixel

result:

True

set_pixel(row=4, column=3, color=4)

function_call:

set_pixel

result:

True

set_pixel(row=4, column=4, color=3)

function_call:

set_pixel

result:

True

set_pixel(row=0, column=0, color=0)

function_call:

set_pixel

result:

True

set_pixel(row=0, column=1, color=0)

function_call:

set_pixel

result:

True

set_pixel(row=0, column=2, color=0)

function_call:

set_pixel

result:

True

set_pixel(row=0, column=3, color=0)

function_call:

set_pixel

result:

True

set_pixel(row=0, column=4, color=0)

function_call:

set_pixel

result:

True

set_pixel(row=1, column=0, color=0)

function_call:

set_pixel

result:

True

set_pixel(row=1, column=1, color=0)

function_call:

set_pixel

result:

True

set_pixel(row=1, column=2, color=0)

function_call:

set_pixel

result:

True

set_pixel(row=1, column=3, color=0)

function_call:

set_pixel

result:

True

set_pixel(row=1, column=4, color=0)

function_call:

set_pixel

result:

True

set_pixel(row=2, column=0, color=0)

function_call:

set_pixel

result:

True

set_pixel(row=2, column=1, color=0)

function_call:

set_pixel

result:

True

set_pixel(row=2, column=2, color=0)

function_call:

set_pixel

result:

True

set_pixel(row=2, column=3, color=0)

function_call:

set_pixel

result:

True

set_pixel(row=2, column=4, color=0)

function_call:

set_pixel

result:

True

set_pixel(row=3, column=0, color=0)

function_call:

set_pixel

result:

True

set_pixel(row=3, column=1, color=0)

function_call:

set_pixel

result:

True

set_pixel(row=3, column=2, color=0)

function_call:

set_pixel

result:

True

set_pixel(row=3, column=3, color=0)

function_call:

set_pixel

result:

True

set_pixel(row=3, column=4, color=0)

working output grid

updated with your changes

[[0 0 0 0 0]
 [0 0 0 0 0]
 [0 0 0 0 0]
 [0 0 0 0 0]
 [5 2 6 4 3]]

image

../../../../_images/008-working_grid4.png

code_execution_result: 4

Non-zero positions (row, col, value): [(0, 1, 2), (0, 3, 4), (0, 4, 3), (1, 0, 5), (2, 2, 6), (3, 0, 5), (3, 1, 2), (3, 3, 4), (4, 0, 5)]

The changes made to the working output grid correctly reflect the transformation we’ve identified. All other cells have been set to 0, and the last row contains the rearranged non-zero values: 5, 2, 6, 4, and 3. This aligns with the prediction from the pre-test phase and the logic of prioritizing the last row, then moving upwards while skipping occupied columns.

update working grid


INSTRUCTIONS:

in this task you will make a function call to set pixels on the grid to achieve the solution

after you update the grid you will be presented with a copy to review

  • set_pixel: update one pixel at a time

  • set_range: update a rectangular subset of pixel

  • set_floodfill: update a contiguous region with a new color

  • submit: when the working grid meets your criteria call submit to check you solution

please call only one function per round so you can review the working grid